Sixth grade math application problems: in the forest, the hound found a running hare 26 meters ahead, and immediately chased after it, the hound has a big step, it ran 5 steps!

This question should not be able to figure out how many steps to catch

Only how many meters to catch the rabbit

Based on "the dog ran 4 steps away from the rabbit ran 9 steps", you can set the dog each step length of 9x meters, then the rabbit each step length of 4x meters.

Based on "the dog runs 5 steps in the time the rabbit runs 8 steps", it can be seen that at the same time the dog runs 5*9x meters = 45x meters, then the rabbit runs 8*4x = 32x meters.

It can be concluded that the ratio of the speed of the dog and the rabbit is 45x:32x = 45:32

Based on "the hound found a running hare 26 meters ahead", it can be known that the difference between the dog and the rabbit is 26 meters, the number of copies of the difference between them is 45-32 = 13, and now ask the dog's 45 copies of how many miles, that is, 26÷32 = 13. is how much distance is 26 ÷ (45-32) × 45 = 90 meters

Arithmetic

The ratio of the speed of the dog to the hare is 5 × 9: 4 × 8 = 45: 32

So the dog catches the hare after running 26 ÷ (45-32) × 45 = 90 meters