You can only access a[0][0] to a[0][3] in that case. Because you are only pointing to a[0], pointer access will be wrong if you cross the boundary.
The pointer array needs to be assigned all the values:
# include<stdio.h>
main()
{
int *p; int a[3][4]={1,2,3,4,5,6,7,8,9,10,11,12};
int *p1[4]; //define pointer array
for(int i=0;i<4;i++)
{
p = a[i]; //a is a two-dimensional array. p = a
p1[i]=p; //
}
printf("the arry is %d\n",*(*(p1+1)+1));
getchar();
}
I think that, as illman2 intended, on the one hand, you can use the array of pointer to a as follows:
# include<stdio.h>
main()
{
int *p; int a[3][4]={1,2,3,4,5,6,7,8,9,10,11,12}; int (*p1)[4];
p=*a;
p1=a;
printf("the arry is %d\n",*(*(p1+1)+1));
}