My sister walks 50 meters per minute from home to school, and my sister walks 45 meters per minute from school. If my sister leaves five minutes earlier than my sister, how far is it to the destinatio

My sister walks 50 meters per minute from home to school, and my sister walks 45 meters per minute from school. If my sister leaves five minutes earlier than my sister, how far is it to the destination school together? Analysis:

According to the meaning of the question, if an elder sister wants to catch up with her elder sister, the distance to catch up is the distance that her elder sister walks five minutes earlier than her elder sister, that is, 45×5=225 meters; Divide 225 by the speed difference between my sister and my sister to get the catching-up time, that is, the time for my sister to go to school from home, and multiply it by my sister's speed, that is, the distance from home to school.

Answer:

Solution: Pursuit distance: 45×5=225 (m);

Catch-up time: 225÷(50-45)=45 (minutes);

Distance from home to school: 50×45=2250 (meters).

It's 2250 meters from home to school.