Pay BC and NE extension lines to f and h respectively.
∵AD⊥CD,BC⊥CD
∴AD∥BC
∴ Quadrilateral AFCD is rectangular.
∴BF=BC-AD=0.4.
∫sinα= BFAB = 0.40 1.30 in Rt△ABF.
∴α≈ 18 .
That is, the inclination angle of AB is about18;
(2)∵NE⊥AF,
∴∠AEH=90 - 18 =72。
∴∠MEN= 180 -∠AEH= 108。
∴MN's length =108×π× 0.85180 ≈1.60 (m).
A: The path length MN of Xiaoming's head movement is about1.60m..