Setting the radius of the trajectory circle as r1, then
r | 21 |
R | 21 |
Substituting the data and solving for r1 = 0.375m
Set the ionic velocity of this circular motion to be v1, qv1B = m
| ||
r1 |
i.e.?v1 =
Bqr1 |
m |
(2) Given that the ions are ejected into the magnetic field with a velocity of v2 in the direction tangent to the inner boundary circle and the orbit is tangent to the outer circle of the magnetic field when the ions are ejected into the magnetic field region with the speed of v2 in the direction tangent to the outer circle of the magnetic field, then with that speed Ions shot into the magnetic field region in all directions cannot penetrate the magnetic field boundary.
Setting the radius of the track circle as r2, we get ?r2 =
R2?R1 |
2 |
By?B =
mv2 |
qr2 |
Answer:
(1) If ions injected into the magnetic field along the radius OM in the region a cannot pass through the magnetic field, the velocity of the particles must not exceed 1.5×107m/s.
( 2) The magnetic induction B of the magnetic field in region b must be at least 2T.