In order to better manage the water quality and protect the environment, a city pollution control company decided to buy 10 sets of sewage treatment equipment, the existing A B two kinds of equipment,

In order to better manage the water quality and protect the environment, a city pollution control company decided to buy 10 sets of sewage treatment equipment, the existing A B two kinds of equipment, each A-type equipment per (1) set each A-type equipment and each B-type equipment need x million yuan, y million yuan, from the meaning of the question:

x?y= 2 3y?2x = 6

,

Solve for

x=12 y=10

.

Answer: each type A equipment and each type B equipment need 120,000 yuan and 100,000 yuan respectively;

(2) let should purchase the model A sewage treatment equipment a, then purchase the model B sewage treatment equipment (10-a), from the meaning of the question:

12a+10(10?a)≤107 240a+200(10?a)≥ 2040

,

Solve: 1≤a≤3.5,

∵a is an integer,

∴a=1,2,3,

Then the B-type purchase of the The number of units in order of 9 units, 8 units, 7 units;

∵ A model of sewage treatment equipment 120,000 yuan a unit, more expensive than the b-type,

∴ less to buy the A-type, more to buy the B-type of the most cost-effective,

Therefore, the purchase of the A-type 1, B-type 9 units,

A: The company purchased the program; ① A-type equipment 1, B-type equipment 9 units; ② A-type equipment 2 units, B-type equipment 8 units; ③ A-type equipment 3 units, B-type equipment 7 units; the first program is the most economical.