(2008? Maoming second model) as shown in the figure, in the vertical placement of the cylindrical container with a mass of m piston sealing part of the gas, the piston and the container wall between c

(2008? Maoming second model) as shown in the figure, in the vertical placement of the cylindrical container with a mass of m piston sealing part of the gas, the piston and the container wall between can (1) take the confined gas as the object of study, the piston rises for the isobaric pressure change, by Gay-Lussac's law has

V

V0

=

T

T0

Getting the outside temperature T=

V

V0

T0=< /tr>

(h0+d)s

h0s

T0=

h0+d

h0

T0

(2) During the rise of the piston, the confined gas overcomes the atmospheric pressure and the gravitational force of the piston to do the work, so the work done by the outside world on the system W=-(mg+P0S)d

According to the first law of thermodynamics, we get that the increased internal energy of the confined gas △U=Q+W=Q-(mg +P0S)d

Answer: ① The temperature of the outside air is

h0+d

h0

T0

②The internal energy of the confined gas increases by Q-(mg+P0S)d