Lian Jie line technology of medical equipment in Jiading district

Solution: (1)∵ In a square ABCD, diagonal BD,

∴∠BDA=∠BDC,

In delta △ADF and delta △CDF,

AD=CD∠BDA=∠BDCDF=DF,

∴△ADF≌△CDF,

∴∠DAF=∠DCF,

∠∠DAF =∠BEF,

∴∠bef=∠dcf;

(2)∫AB∨CD,

∴∠BAE=∠CGE,

∠∠BEF =∠DCF;

∠BAE = 90-∠DAF∠FCE = 90-∠DCF,

∴∠BAE=∠FCE,

∴∠CGE=∠FCE,

∴△FCE∽△FGC,

∴FCEF=FGFC,

FC = AF,

∴AF2=FE? FG。