What kind of medical equipment is eomc?

AM is the center line of BC side.

S△AMC=S△AMB,S△OMC=S△OMB

So S△AOC=S△AOB

AE/EB=S△ACE/S△BCE=S△AOE/S△BOE

So AE/EB=S△AOC/S△BOC.

In the same way; In a similar way

So AD/CD=S△AOB/S△BOC

So ad/CD = s △ AOB/s △ BOC = s △ AOC/s △ BOC = AE/EB.

So ED//BC

You can also use the inverse theorem of Seva's theorem.