Urgent! Be specific! Excuse me, how can I get to the dental clinic of the Second Affiliated Hospital of Shantou University from the intersection of Xiashan Feng Dan by car?

1. It's 2.0km drive from Feng Dan Road (take a taxi * * *), and the cost is about 10 yuan. After 23:00 pm, the cost will be about 10 yuan). Take a long-distance bus to Xiashan Bus Station in Shantou and get off at Shantou Station. At the bus station (bus station), transfer to No.26 (take the station 17) and get off at the Second Affiliated Hospital of Shantou University. Go about 80 meters to the Second Affiliated Hospital of Shantou University School of Medicine.

2. Take a taxi, * * * the journey is 46. 1 km, and the cost is about 139 yuan. After 23:00 p.m., the cost is about 144 yuan. Note: The information is for reference only and cannot be used as a basis for payment. This fee does not include tolls and bridge fees, and traffic jams and other factors may greatly increase the cost.

3. It's 2.0km drive from Feng Dan Road (take a taxi * * *), and the cost is about 10 yuan. After 23:00 in the evening, the fare is about 10 yuan) to Xiashan Bus Station (outside the station), take Jieyang Puning Liusha Bus Station-Shantou Bus Station (take 2 stops) and get off at Shantou Bus Station (long-distance station), then walk to the bus station (bus station) and transfer to No.26 (take 17 station) and get off at the Second Affiliated Hospital of Shantou Medical University. Go about 80 meters to the Second Affiliated Hospital of Shantou University School of Medicine.

4. It's 2.0km drive from Feng Dan Road (take a taxi * * *), and the cost is about 10 yuan. After 23:00 pm, the fare is about 10 yuan) to Xiashan Bus Station (outside the station), take Jieyang Puning Liusha Bus Station-Shi Zhuan Bus Station (take 2 stops), get off at Shi Zhuan Bus Terminal (long-distance station), cross the road, turn left to Xidi Wharf Terminal, and change to 1 Road (take 25 stops). Go about 80 meters to the Second Affiliated Hospital of Shantou University School of Medicine.