It is known that the three vertices of triangle AbC are A(-1,-4),B(5,2),C(2 root 2-1,4). Prove that triangle ABC is equal

That's easy ~ you find the coordinates of vectors AB, BC, AC, and then go to their modulus lengths respectively, to prove, for equal ~~~

Then AM, M is the midpoint of BC so m{(-2+4)/2,(-1+7)/2},then AM coordinates is also very easy, then to find the length of his modulus on the line ~

For the proof that diagonals are equal, you Simply take A as the origin, the coordinates of B, C, D constant with an algebraic representation, for the proof

All not difficult, as long as you are willing to go to spend time on the problem~