Let the speed of the bowl to the highest point be v0 and the angular velocity of wrist rotation be w,
mv20R=mg
Solution: r = 0.8m
From ω=vR, ω = 52 radians/second ≈ 7. 1 radians/second.
(2) As shown in the figure on the right, analyze the stress of the drum. Let the maximum speed of the lowest point be v and the rope tension be t, then according to Newton's second law:
T-mg=mv2R
That is v=T? mgmR
If T≤30N, v≤4m/s,
The speed of the drum at the lowest point should not exceed 4m/s. 。
A:
(1) If water is not splashed all the time, the angular velocity of the actor's wrist rotation should be around 7.1rad/s. 。
(2) If the maximum carrying capacity of the rope is 30N, the speed of the bowl at the lowest point should not exceed 4m/s. 。