How to say the queuing problem in primary school mathematics?

The queuing problem refers to the problem that some people line up in a row or a column, and one or more of them are observed to find out the total number of people or how many people there are before and after. To solve this kind of problem, we should pay attention to: as an observation point, people cannot be added repeatedly or omitted.

First question? The students of the first team lined up in a row. There are five people in front of Xiao Ming and four people behind Xiao Ming. How many people are there in a team?

[Analysis] It is best to use schematic diagrams to solve such problems. (As shown below, δ represents Xiao Ming and● represents other students in the group)

As can be seen from the picture, "five people in front of Xiao Ming and four people behind Xiao Ming" add up to 5+4=9 (people). Among the nine people, there is no Xiao Ming, plus Xiao Ming himself. The first team has 9+ 1 = 10 (people). The formula is 5.

The second question? Students stand in a row, counting from left to right, Xiaolin stands in the sixth place, and Jiao Xiaolin stands in the eighth place from right to left. How many students are there in this line?

[Resolution] Draw a schematic diagram. (△ stands for Xiao Lin, ● stands for other students)

As we can see from the picture, "Xiao Lin stands in the sixth place from left to right" means that among the six students from left to right, including Xiao Lin, "Xiao Lin stands in the eighth place from right to left" means from right to right.

The eight students counted from the left also include Xiao Lin.

If you combine the two results, there will be two Kobayashi, which means adding Kobayashi again. So 1 Kobayashi should be subtracted from the synthesis result. So on this line,

There are 6+8- 1= 13 students.

The formula is: 6+8- 1= 13 pieces.

A: There are 13 students in this line.

The third question? There are 12 students in the line, 5 students in front of Xiaojiang and many students behind Xiaojiang. (Xiao Jiang is represented by δ, while other students are represented by χ)

[Resolution] Judging from the total number of students in 12, five students in front of Xiaojiang were removed, and the remaining seven students included Xiaojiang in addition to the students behind Xiaojiang. So we have to remove Xiaojiang 1 from the remaining seven students, and we can get that the number of students behind Xiaojiang is 7- 1=6 (1). Formula: 12-5- 1 = 6 (pieces) A: There are 6 students behind Xiaojiang.

The fourth problem is that the school dance team rehearses dances, and 15 people stand in a row. From left to right, Fangfang ranked fourth, from right to left, and Tian Tian ranked sixth. How many people are there between Fangfang and Tian Tian?

[Resolution] Draw a schematic diagram. (△ stands for Fangfang, ● stands for sweetness, and the heart stands for other players.

As can be seen from the picture, "Fangfang ranks fourth from left to right" means: Fangfang is four people from the first one on the left; "From right to left, Sweets ranks sixth" Description: The number from the right is six. Put these two parts together-* * is 4+6=

10 (piece). 15 people Remove this 15 people, and the rest is the number between Fangfang and Tian Tian. Formula: 15-(4+6)=5 A: There are five people between Fangfang and Tian Tian.