The first thing you need to do is to make sure that you are paying for your own health insurance, and that you are paying for it yourself.

No it's not cost-effective

The answer is definitely no it's not cost-effective because paying for employee health insurance on your own means that you will have to pay the entire amount yourself, which can be financially stressful, but it is possible to pay this way if you have the financial means to do so. If you pay for your own employee health insurance, you will have to bear the full cost of the premiums, so the pressure will be relatively high.

One, is it cost-effective to pay for your own employee health insurance? The first thing you need to do is to make sure that you have the right amount of money to pay for your health insurance. Medicare? The current basic health insurance program is designed to help individuals who are flexibly employed to pay for their health insurance. Basic Medical Insurance? The policy stipulates that, up to 2113 to the retirement age, male participants 5261 contribution years to complete 30 years, female participants to complete 25 years of contribution years. Failure to meet the required payment of health insurance years 4102 limit, the retirement can be a one-time liquidation.? Medicare has a wide range of medical expenses, which are generally differentiated according to the characteristics of their medical services, and mainly include doctors' outpatient fees 1653, medication, hospitalization fees, nursing costs, hospital fees, surgical costs, and various inspection costs. Medical expenses are the various costs incurred by the patient for treatment, which includes not only the doctor's medical and surgical fees, but also hospitalization, nursing care, hospital equipment and other costs. Secondly, they pay for employee health insurance every year to pay how much money? Medical insurance is mainly divided into employee medical insurance and the city copy township residents medical insurance, different types of contribution amount is different.