(1) The graduation value of the spring dynamometer is 0.1N, and the reading is: 2.5N;
(2) W is useful = Gh = 1.5N × 0.3m = 0.45 J;
W total=FS=2.5N×0.2m=0.5J;
η=W useful W total×100=0.45J0.5J×100=90
(3) Because the lever itself has gravity, when lifting the object, the lever must also be lifted, that is, overcoming the weight of the lever to do work, there will be extra work;
So the answer is: 2.5; 90; because When using a lever, you need to overcome the lever's own weight (overcoming friction) and other work.