Known from: AB=2, BC=32, AC= 10, AD=2, PD=3, AP = 5;;
So: ABAD=2, BCPD=2, kappa = 2; Namely: abad = bcpd = capa
So △ ABC ∽△ ADP
(2) As shown in the figure,
△ACD' is an isosceles right triangle;
Because AC=AD= 10, CD=25, CD2=AC2+AD2,
So △ACD' is an isosceles right triangle.
(3) Because △ACD' is an isosceles right triangle, ∠ ACD = ∠ OCA+∠ OCD = 45.