s | |
s | |
C=
9×10?12×50×10?6 |
0.6×10?3 |
0.6×10?3 | tr>
The capacitor becomes 0.75+0.25=1×10-12F;
The capacitance of the capacitor is changed from C=?0
s |
d |
d′=
9×10?12×50×10 ?6 |
0.50×10?12 |
So, it should be pressed down to 0.60-0.45=0.15mm;
Thus The answer is: 1; 0.15.