Pcb processing of medical equipment in Hohhot

Solution: Solution: Connect BC.

∵AB is the diameter⊙ O,

∴∠BCP=90。

According to the equal circumferential angle of the same arc:

∠A=∠D,∠DCA=∠PBA

∴△PCD∽△PBA.

∴CDAB=PCPB=cos∠BPC.

So choose B.