When the magnet passes through the coil at a uniform speed to the right, the N pole is close to the coil, and the induced current of the coil will always hinder the relative motion of the magnetic pole and give the magnetic pole a force to the left. Then the magnetic pole will give the coil a force to the right, and the coil will stand still because of the friction to the left. When the N pole leaves the coil, the induced current of the coil will always hinder the relative motion of the magnetic pole and give the magnetic pole a force to the left, so the magnetic pole will give the coil a force to the right, and the coil will stand still because of the friction to the left.
In CD, when the original magnetic flux increases, the magnetic field of induced current is opposite to the original magnetic field; When the original magnetic flux decreases, the magnetic field of the induced current is the same as the original magnetic field. When the N pole of the magnet approaches the coil to the right, the upward magnetic field in the coil increases, and the magnetic field of the induced current is downward, so the induced current is clockwise. When the N pole of the magnet is far away from the coil to the right, the upward magnetic field in the coil decreases, and the magnetic field of the induced current is upward, so the induced current is counterclockwise. When the magnetic pole of the magnet approaches the coil, the downward magnetic field is enhanced and the induced current is upward. So the induced current is counterclockwise. When the S pole is far away from the coil, the downward magnetic field is weakened and the induced current is downward, so the induced current is clockwise. So, C is right and D is wrong.
Therefore: AC