In the equilibrium state, the resultant force of these three forces is zero, that is, F float +F-G=0 and buoyancy F float = G-F. According to the experimental data in the table, the buoyancy of the first experiment is zero.
Then the metal cylinder is neutral G=F 1=4.75N, f float 5=G5-F5=4.75N-2.75N=2.00N, f float 6=G6-F6=4.75N-2.25N=2.50N,
F float 7=G7-F7=4.75N-2.25N=2.50N, F float 8 = G8-F8 = 4.75n-2.25n = 2.50n, and the experimental data are shown in the table below.
The experimental sequence is12345678h/cm024681014f/n4.754.253.752.252.25f float/n0.501.00. 2.00 2.50? 2.50? 2.50(2) First draw points on the coordinate paper according to the experimental data in the table, and then draw them according to the lines of the drawn points. The image is shown in the figure below.
According to the F-float -h image:
Before the metal cylinder is completely immersed in water, with the increase of the liquid volume discharged by the metal cylinder, the buoyancy also increases, and it shows a positive proportional function image; When the metal cylinder is completely immersed in water, the buoyancy of the metal cylinder remains unchanged with the increase of the depth of the metal cylinder immersed in water, and the buoyancy of the object has nothing to do with the depth of the object immersed in water; From this, we can draw the following conclusions:
Buoyancy is related to the volume of liquid discharged by an object.
(2) In the same liquid, the buoyancy of an object is directly proportional to the volume of liquid displaced by the object.
Buoyancy has nothing to do with the depth of the object immersed in the liquid.
So the answer is: (1) as shown in the above table; (2) The image is as shown above; Experimental conclusions: ① buoyancy is related to the volume of liquid displaced by the object; (2) In the same liquid, buoyancy is directly proportional to the volume of liquid displaced by the object; (3) buoyancy has nothing to do with the depth of the object immersed in the liquid.