Known: a sample data (a set of data); Average population (a data).
Case:
Compare the gap between the physical health level of a college student and the average level of the whole province.
Known: the data of physical health test of students in our school (a set of data). The average level of the province (the average physical health of college students in the province is divided into one data, such as 80 points).
1.SPSS operation:
1) analysis-mean comparison-single sample t test
2) Select "Physical Fitness Score" in the "Test Variables" list on the right. Enter the inspection value "80". (As mentioned above, the average physical health of college students in the province is 80%). (the choice of this step is actually to determine the two sides of the comparison. The test variable is a known sample. ) Click OK.
2.SPSS results
"significance" is often called "p" value.
Judgment method:
When p&; Gt0.05, the difference was not statistically significant. When P0.05, the difference was statistically significant.
There is a statistical difference between college students' physical health level and the provincial level (P & amp； Lt0.0 1)。 But the result only tells us that there are differences, but does not tell us whether the students' physical health level in this university is higher than that in the whole province. Therefore, it is necessary to combine the sample average (specialist) and the overall average (provincial average) to further judge. The sample average is 84.00, which is higher than the overall average of 80. It is concluded that the physical health level of students in this school is obviously higher than that of the whole province.
Related Q&A: How to calculate the P value manually in spss? 1. First, open the data table and compare the mean values of paired design samples.
2. Then choose analysis-comparison mean-paired sample T test.
3. Then drag the two variables to be paired into the paired variables box.
4. Select the option and adjust the confidence interval to 95%.
5. Click Boot again to cancel booting.
6. Finally, we can see the results, and the P value is less than 0.05, so we can think that there is a statistical difference between the paired samples.