As shown in the figure is known to parabola y = ax square plus bx + 5 through a negative 0 b negative four negative three two points and the x-axis of another intersection for the top c

solution a = 1

b = -4

c = 0 ;

∴ ∴ the analytic formula of the parabola for the y = x2-4x;

(2) the parabola y = x2 - 4x and x-axis of the intersection of the other point of the coordinates of the c (4, 0), connect EM;

∴ radius of ⊙ M is 2, i.e. OM=DM=2;

∵ ED, EO are tangent to ⊙ M,

∴ EO=ED, △EOM??EDM;

∴Squadrilateral EOMD=2S△OME=2× OM?OE=2m; set the coordinate of the point D as (x0,y0),

∵S△DON=2S△DOM=2× OM×y0=2y0,

when S quadrilateral EOMD=S△DON,i.e., 2m=2y0,m=y0;

∵m=y0,ED‖x-axis,

∵ED is the tangent line,

∴ the coordinates of point D is (2,2);

∵ P is on the line ED, so let the coordinates of point P be (x,2),

∵ P is on the parabola,

∴ 2 = x2-4x,

Solve x = 2 ± root 6 ;

∴ P (2 + root 6,2) or P (2 - root 6 ,2) is the required.